From: Domen Puncer <domen@coderock.org>
Code looks like it intended to parse "%%" in pattern string as "%". Fix
it, so it really does that.
Compile and run tested.
Signed-off-by: Domen Puncer <domen@coderock.org>
Signed-off-by: Andrew Morton <akpm@osdl.org>
---
25-akpm/lib/parser.c | 1 +
1 files changed, 1 insertion(+)
diff -puN lib/parser.c~lib-parser-fix-%%-parsing lib/parser.c
--- 25/lib/parser.c~lib-parser-fix-%%-parsing 2004-11-07 23:55:21.698766824 -0800
+++ 25-akpm/lib/parser.c 2004-11-07 23:55:21.702766216 -0800
@@ -47,6 +47,7 @@ static int match_one(char *s, char *p, s
else if (*p == '%') {
if (*s++ != '%')
return 0;
+ p++;
continue;
}
_